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If mass of U^(235)=235.12142 a.m.u., mas...

If mass of `U^(235)=235.12142 a.m.u.`, mass of `U^(236) =236.1205 amu`, and mass of neutron `=1.008665 am u`, then the energy required to remove one neutron from the nucleus of `U^(236)` is nearly about.

A

75 MeV

B

6.5 MeV

C

1 eV

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B

(b) Mass of one atom of `U^235`
`=235.121420` amu
Mass of one neutron `=1.008665` amu
Sum of the masses of `U^235` and neutron
=`236.130085 = 236.130` amu
Mass of one atom of `U^236`
=`236.123050`amu
=`236.123` amu
Increase in mass when one neutron is removed from
`U^236 = 236.136 - 236-123`
`=0.007` amu
`:.` Energy required to remove one neutron
=`0.007 xx 931 MeV`
=`6.517 MeV = 6.5 MeV`.
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