An aqueous solution of aniline of concentration `0.24` M is prepared. What concentration of sodium hydroxide is needed in this solution so that anilinium ion concentration remains at `1xx10^(-8)M` ? `(K_(a)for C_(6)H_(5)NH_(3)^(+)=2.4xx10^(-5)M)`

Explanation

To solve the problem, we need to find the concentration of sodium hydroxide (NaOH) required to maintain the concentration of anilinium ion (C6H5NH3+) at \(1 \times 10^{-8} \, M\) in a solution of aniline (C6H5NH2) with a concentration of \(0.24 \, M\). We will use the relationship between the acid dissociation constant (Ka) and the base dissociation constant (Kb) for this calculation.

### Step-by-step Solution:

1. **Write the equilibrium reaction:**
The hydrolysis of aniline can be represented as:
\[
\text{C}_6\text{H}_5\text{NH}_2 + \text{H}_2\text{O} \rightleftharpoons \text{C}_6\text{H}_5\text{NH}_3^+ + \text{OH}^-
...