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Two satelites of a planet have period 32...

Two satelites of a planet have period 32 days and 256 days. If the radius of orbit of former is R, find the orbital radius of the latter.

Text Solution

Verified by Experts

As `T^(2) prop R^(3)` or `R prop T^(2//3)`
`:. (R_(2))/(R_(1)) = ((r_(2))/(r_(1)))^(3//2)` or `R_(2) = R ((256)/(32))^(3//2)` = 4R`
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Knowledge Check

  • The radius of a planet is 74 xx 10^(3) km . A satellite of this planet completes one revolution in 16.7 days. If the radius of the orbit of satellite is 27 times the radius of planet, then the mass of planet is

    A
    `2.3 xx 10^(27) kg`
    B
    `2.3 xx 10^(30) kg`
    C
    `2.3 xx 10^(32) kg`
    D
    `2.3 xx 10^(42) kg`
  • If the radius of first Bohr's orbit is r, then radius of second orbit will be

    A
    `2r`
    B
    `r/2`
    C
    `4r`
    D
    `sqrt2r`
  • If r is the radius of first orbit, the radius of nth orbit of the H atom will be:

    A
    `rn^(2)`
    B
    `rn`
    C
    `(r)/(n)`
    D
    `r^(2)n^(2)`
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