Home
Class 11
PHYSICS
The distance of planet Jupiter from the ...

The distance of planet Jupiter from the Sun is `5.2` times that of the earth. Find the period of revolution of Jupiter around the Sun.

Text Solution

Verified by Experts

For the earth, `T_(1) = 1 year` , `r_(1) = 1 AU`
For planet venus, `T_(2) = ? , r_(2) = 0.72 AU`.
As `(T_(2)^(2))/(T_(1)^(2)) = (r_(2)^(3))/(r_(1)^(3))` or `T_(2) = T_(1) ((r_(2))/(r_(1)))^(3//2) = 1 ((0.72)/(1))^(3//2)`
`= 0.61 year`
`= 0.61 xx 365 = 233 days`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVIATION

    PRADEEP|Exercise PROBLEMS FOR PRACTIVE|47 Videos

  • GRAVIATION

    PRADEEP|Exercise PROBLEMS FOR PRACTIVE B|1 Videos

  • GRAVIATION

    PRADEEP|Exercise FILL IN THE BLANKS|11 Videos

  • BEHAVIOUR OF PERFECT GAS & KINETIC THEORY

    PRADEEP|Exercise Assertion - Reason Type questions|14 Videos

  • KINEMATICS

    PRADEEP|Exercise 1 NCERT Comprehension|4 Videos

Similar Questions

Explore conceptually related problems

Earth completes one revolution around the Sun in

The mean distance of Mars from the sun in 1.524 times that of the Earth from the sun. Find the number of years requires for Mars make one revolution about the Sun.

Knowledge Check

  • The distance of a planet from the sun is 5 times the distance between the earth and the sun. The time period of the planet is :

    A
    `6^(3//2)` T yr
    B
    `5^(3//2)` T yr
    C
    `5^(3//1)` T yr
    D
    `5^(1//2)` T yr

  • The distance of a planet from the sun is 5 times the distance between the earth and the sun. The time period of the planet is :

    A
    `6^(3//2)` T yr
    B
    `5^(3//2)` T yr
    C
    `5^(3//1)` T yr
    D
    `5^(1//2)` T yr

  • The distance of a planet from the sun is 5 times the distance between the earth and the sun. The time period of the planet is

    A
    `5^(3//2)` years
    B
    `5^(2//3)` years
    C
    `5^(1//3)` years
    D
    `5^(1//2)` years

    • Similar Questions

    Explore conceptually related problems

    If the mass of the sun is 2 xx 10^(30) kg , the distance of the earth from the sun is 1.5 xx 10^(11) m and period of revolution of the earth around the sun is one year ( = 365.3 days ) , calculate the value of gravitational constant .

    The mean distance of a planet from the sun is apprximately 1/4 times that of earth from the sun. Find the number of years required for planet to make one revolution about the sun.

    The mean distance of Mars from the Sun is 1.52 times that of Earth from the Sun. From Kepler's law of periods, calculate the number of years required for Mars to make one revolution around the Sun, compare your answer with the value given in Appendix C.

    The radius of Jupiter is 11 times the radius of the Earth. Calculate the ratio of the volumes of Jupiter and the Earth. How many Earths can Jupiter accommodate?

    The ratio of the distances of two planets from the sun is 1.38. The ratio of their period of revolution around the sun is

    Home
    Profile