Compute the elongation of the steel wire and brass wire in the given

Given unloaded length of steel wire = 2.0 m, unloaded length of brass wire = 1.0m. Area of cross-section of each wire `= 0.049 cm^2.`
`Y_(steel) = 2xx10^(11)Pa`
and `Y_(Brass) = 0.90 xx 10^(11)P_a , g = 9.8 ms^(-2)`

Answer

`2.0xx10^(-4) m; 2.66 xx 10^(-4)m`

Explanation

For steel wire, `F = 4 + 6 = 10 kg" "f = 10xx 9.8 N`
`Delta l = (Fxxl)/(YxxA) = (10xx9.8 xx 2.0)/(2xx 10^(11) xx(0.49 xx 10^(-4))`
`= 2.0xx10^(-4)m`
For brass wire, `F = 6 kg" "f = 6xx9.8 N `
`Delta l = (6xx9.8 xx2.0)/(0.90xx10^(11)xx(0.049 xx 10^(-4))`
` = 2.66 xx 10^(-4)m`