The volume of steam produced by `1g` of water at `100^(@)C` is `1650 cm^(3)`. Calculate the change in internal energy during the change of state. Given `J= 4.2xx10^(7) erg`.
`cal.^(-1), d= 981 cm^(s-2)`. Latent heat of stream `= 540 cal. G^(-1)`

Explanation

To calculate the change in internal energy during the change of state of water to steam, we will follow these steps:

### Step 1: Identify the given values
- Mass of water, \( m = 1 \, \text{g} \)
- Volume of steam produced, \( V_2 = 1650 \, \text{cm}^3 \)
- Initial volume of water, \( V_1 = 1 \, \text{cm}^3 \) (since the density of water is \( 1 \, \text{g/cm}^3 \))
- Latent heat of steam, \( L = 540 \, \text{cal/g} \)
- Mechanical equivalent of heat, \( J = 4.2 \times 10^7 \, \text{erg/cal} \)
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