Suppose while sitting in a parked car, you notice a jogger approaching towards you in the rear view mirror of `R = 2 m`. If the jogger is running at a speed of `5 ms^-1`, how fast is the image of the jogger moving, when the jogger is
(a) 39 m
(b) 29 m
(c) 19 m and
(d) 9 m. away ?

Explanation

To solve the problem step by step, we will use the concepts of ray optics, specifically the properties of a convex mirror. The key points to remember are the mirror formula, magnification, and how to relate the speed of the object to the speed of the image.

### Given:
- Radius of curvature of the mirror, \( R = 2 \, \text{m} \)
- Speed of the jogger (object), \( v_o = 5 \, \text{m/s} \)

### Step 1: Determine the focal length of the mirror
For a convex mirror, the focal length \( f \) is given by:
...