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1 mol of CH(4) contains...

1 mol of `CH_(4)` contains

A

(a)`6.02xx10^(23)` atoms of `H`

B

(b)`4 g` atom of Hydrogen

C

(c )`1.81xx10^(23)` molecules of `CH_(4)`

D

(d)`3.0 g` of carbon

Text Solution

Verified by Experts

The correct Answer is:
B

1 mole of `CH_(4)` contains `4` mole of hydrogen atom, i.e., `4 g` atom of hydrogen.
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Most combustion reactions occur in excess of O_(2) (i.e., more than enough O_(2) to burn the substance completely). Calculate the mass of CO_(2) (in grams) produced by buring 4.00 mol of CH_(4) in excess O_(2) . Strategy: using the balanced equation {:(CH_(4), + 2O_(2), rarr CO_(2), + 2H_(2) O),(1mol, 2mol,1 mol,2mol),(16.0 g,2(32.0)g,44.0g,2(18.0g)):} we find out that 1 mol of CH_(4) is chemically equivalent to 1 mol of CO_(2) or 44.0g of CO_(2) .

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Knowledge Check

  • 1.6g of CH_(4) contains same number of electrons as in :

    A
    `4.48L` of `CH_(4)at NTP`
    B
    `6.02xx10^(22) "molecules of" CH_(4)`
    C
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    D
    `2.24 L` of `O_(2) at STP`
  • Assertion: 1 mol of O and 1 mol of O_(2) contain equal number of particles. Reason: 1 mol of molecules is always double than 1 mol of atoms in all diatomic molecules.

    A
    Assertion and reason both are correct statements and reason is correct explanation for assertion.
    B
    Assertion and reason both are correct statements but reason is not correct explanation for assertion.
    C
    Assertion is correct statements but reason is wrong statement.
    D
    Assertion is wrong statement but reason is correct statement.
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    A
    `C_(5)H_(10)O_(5)`
    B
    `C_(3)H_(6)O_(3)`
    C
    `C_(4)H_(8)O_(4)`
    D
    `C_(6)H_(12)O_(6)`
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