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If the degree of ionization of water be ...

If the degree of ionization of water be `1.8xx10^(-9)` at `298 K`. Its ionization constant will be

A

`1.8xx10^(-16)`

B

`1xx10^(-14)`

C

`1xx10^(-16)`

D

`1.67xx10^(-14)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(a)=(K_(W))/([H_(2)O])=(10^(-14))/(55.5)=1.8xx10^(-16)`
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Knowledge Check

  • If the degree of ionization of water be 1.8 xx 10^(-9) at 298K. Its ionization constant will be

    A
    `1.8 xx 10^(-16)`
    B
    `1 xx 10^(-14)`
    C
    `1 xx 10^(-16)`
    D
    `1.67 xx 10^(-14)`

  • If the degree of ionization of water is 1.8xx10^(-9) at 298K . Its ionization constant will be

    A
    `1.8xx10^(-16)`
    B
    `1xx10^(-14)`
    C
    `1xx10^(-16)`
    D
    `1.67xx10^(-14)`

  • The degree of ionization increases

    A
    with increase in concentration of the solution
    B
    on addition of excess of water to the solution
    C
    on decreasing the temperature of the solution
    D
    on stirring the solution vigorousoly.

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