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The crystal field splitting energy for o...

The crystal field splitting energy for octahedral`(Delta_(0))` and tetrahedral `(Delta_(t))` complexes is related as .

A

(a) `Delta_t=4/9Delta_o`

B

(b) `Delta_t=1/2Delta_o`

C

(c) `Delta_o=1/2Delta_t`

D

(d) `Delta_o=4/9Deltat`

Text Solution

Verified by Experts

The correct Answer is:
A

The crystal field splitting energy in case of tetrahedral complexes where only four ligands approach the central metal ion causing weak field around it is smaller than the crystal field splitting energy of octahedral complexes where six ligands approach the central metal ion and create a strong field around it. The two are related as `Delta_t=4/9Delta_0`.
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Knowledge Check

  • The crystal field splitting energy for octahedral (Delta_(0)) and tetrahedral (Delta_(1)) complexes is related as

    A
    `Delta_(t)=-(1)/(2)Delta_(0)`
    B
    `Delta_(t)=-(4)/(9)Delta_(0)`
    C
    `Delta_(t)=-(3)/(5) Delta_(0)`
    D
    `Delta_(t)=-(2)/(5)Delta_(0)`
  • The crystal field splitting energy for octahedral complex (Delta_(0)) and that for tetrahedral complex (Delta_(t)) are related as:

    A
    `Delta_(t)=4/9 Delta_(0)`
    B
    `Delta_(t)=0.5 Delta_(0)`
    C
    `Delta_(t)=0.33 Delta_(0)`
    D
    `Delta_(t)=9/4 Delta_(0)`
  • The crystl field splitting energy for octahedral complex (Delta_(0)) and that for tetrahedral complex (Delta_(1)) rae related as :

    A
    `Delta_(t)=(4)/(9) Delta_(0)`
    B
    `Delta_(t)=0.5 Delta_(0)`
    C
    `Deltat=0.33Delta_(0)`
    D
    `Deltat=(9)/(4)Delta_(0)`
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    The magnitude of crystal field stabilisation energy (CFSE of Delta_(1) ) in tetrahedral complexes is considerably less than that in the octahderal field. Because

    The magnitude of crystal field stabilization energy (CFSE or Delta t) in tetrahedral complexes is considerably less than in octahedral field. This is because