Consider two configurations of a system of three particles of masses `m`, `2m` and `3m`. The work done by gravity in changing the configuration of the system from figure (i) to figure (ii) is

Options

A. zero
B. `-(6Gm^(2))/a(1+1/(sqrt(2)))`
C. `-(6Gm^(2))/a(1-1/(sqrt(2)))`
D. `(6Gm^(2))/(a)(2-1/(sqrt(2)))`

Answer

C

Explanation

`GPE=(-Gm_(1)m_(2))/(r), W=GPE_(2)-GPE_(1)`