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Nitric acid (HNO(3)) is 1.6% H, 22.2 %N,...

Nitric acid `(HNO_(3))` is `1.6% H, 22.2 %N`, and `76.2% O` by mass. All pure samples of `HNO_(3)` have this compostion according to the

A

law of mutliple proportions

B

law of reciprocal proportions

C

law of definite propotions

D

law of conservation of mass

Text Solution

Verified by Experts

The correct Answer is:
C
According to the law of define proptions, all pure samples of a given compond always consist of the same elements combined in the same proportions by mass.
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N_(2)O is an acid anhydride of HNO_(3) .

Cancerntrated HNO_(3) used in the laboratory is usually 69% by mass of HNO_(3) . The density of HNO_(3) . The density of HNO_(3) solution is 1 .41 g cm^(3) . Find The molarity.

Knowledge Check

  • Concentrated HNO_(3) is 63% HNO_(3) by mass and has a density of 1.4g//mL . How many millilitres of this solution are required to prepare 250mL of a 1.20 M HNO_(3) solution ?

    A
    `18.0`
    B
    `21.42`
    C
    `20.0`
    D
    `14.21`

  • Assertion: Nitric acid can oxidise H_(2)S Reason: Amorphous sulphur is formed when conc HNO_(3) reacts with H_(2)S

    A
    Both A and R are correct and R is the correct explanation of A
    B
    Both A and R are correct and R is not the correct explanation of A
    C
    A is correct R is wrong
    D
    A is wrong R is correct

  • The following sequence of reaction occurs in commical production of aqueous nitric acid. NH_(3)(g)+O_(2)(g) rarr NO(g)+H_(2)O(l) NO(g)+O_(2)(g)rarr NO_(2)(g) NO_(2)(g)+H_(2)O(l) rarr HNO_(3)(aq)+NO(g) In an industry , 378 kg of HNO_(3) was required to be produced. If % yield of reaction(i),(ii) and (iii) is 85% , 60% and 50% respectively , then mass (kg) of NH_(3) required is : [NO produced in reaction(iii) is not re-used in reaction-(ii)]

    A
    30
    B
    600
    C
    6000
    D
    300

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    Concentrated HNO_(3) is 69% by mass of nitric acid. Calculate the volume of the solution which contains 23 g of HNO_(3) . (Density of concentrated HNO_(3) solution is 1.41 g ml^(-1))

    P + HNO_(3) = HPO_(3) + NO + H_(2) O

    H_(2) S + HNO_(3) = NO + S + H_(2) O

    Copper (Cu) and (Zn) react differently with HNO_(3) as follows: Cu + 4H^(o+) (aq) + 2NO_(3)^(ɵ) (aq) rarr 2NO_(2)(g) _ Cu^(2+) + 2H_(2)O 4Zn +10 H^(o+) (aq) + 2NO_(3)^(ɵ) (aq) rarr NH_(4)^(o+) + 4Zn^(2+) + 3H_(2)O What volume of 2.0 M HNO_(3) would react with 10.0g of a brass (90.% Cu, 10.0% Zn) according to the above equation?

    Dil. HNO_(3) , contains 20% acid and it dissolves 10 g CaCO_(3) . The quantity of acid is

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