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For Be^(3+) ion, the degeneracy of the 3...

For `Be^(3+)` ion, the degeneracy of the `3rd` enegry level is equal to

A

nine

B

six

C

three

D

seven

Text Solution

Verified by Experts

The correct Answer is:
A
Degeneracy is equal to the number of orbitals that have the same enegry. Different subshells of a particular shell have different energues in case of multi-electron atoms. However, in `H` atom or `H-`like ion such as `Be^(3+)`, these have the same enegry. Thus,`3s, 3p_(x),3p_(y),3p_(z),3d_(xy),3d_(xz),3d_(yz),3d_(x^(2)-y^(2))`, and `3d_(z^(2))` all possess the same enrgy.
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Knowledge Check

  • Not considering the electronic spin, the degeneracy of the second excited state (n = 3) of H atom is 9, while the degeneracy of the second excited state of H^(-) is :

    A
    3
    B
    5
    C
    2
    D
    4

  • 1.8 gm of H-atom sample is excited by radiations. The study of spectra indicates that 27% of the atoms are in 3rd energy level, 15% of atoms in 2nd energy level and test in ground state

    A
    Number of atoms in 2nd energy level is `1.626 xx 10^(23)` atoms
    B
    Number of atoms in 3rd energy level is `2.9268 xx 10^(23)` atoms
    C
    Number of atoms in Ground state is `6.2872 xx 10^(23)` atoms
    D
    All are correct

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