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The electronic conguration 1s^(2)2s^(2)2...

The electronic conguration `1s^(2)2s^(2)2p^(6)3s^(2)3d^(9)` represnts a

A

metal atom

B

nonemtallic atom

C

metallic cation

D

nonmetallic anion

Text Solution

Verified by Experts

The correct Answer is:
C
If we add the total number of electron `(27e^(-)s)`and rewrite the configuration, we get
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(7)4s^(2)`
or simply `[Ar] 3d^(7)4s^(2)`
For `28 e^(-)s`, electronic configuration is `[Ar] 3d^(8) 4s^(2)`
For `29e^(-)s`, electronic configuration is `[Ar]3d^(10)4s^(1)`.
If we take out `2e^(-)s`, we get the given configuration. Since the last `e^(-) (Z = 29)` enters the `(n - 1)d` subshell, it is a `d`-block metal, copper `(Cu)`. The given configuration describes the cupric ion `(Cu^(2+))`, a metallic cation.
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