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In propylene, H(2)C=CH-CH(3), the C=C-C ...

In propylene, `H_(2)C=CH-CH_(3)`, the `C=C-C` bond angle is

A

`120^(@)`

B

`121^(@)`

C

`124^(@)`

D

`126^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C

In propylene, the `C=C-C` bond angle `(124^(circ))` is larger than the corresponding `C=C-H` bond angle `(121^(circ))` in ethylene because the `CH_(3)` group has more `e^(-)s` than `H` and is, thus, repelled more by the `e^(-)s` of the `C=C` bond.
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R SHARMA-ALKENES-Question Bank
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