The molar conductance is given by the relation (M `=` concentration in molarity)

Options

A. `Lambda_(m) = 1000(k)/(M)`
B. `Lambda_(m) = 1000(M)/(k)`
C. `Lambda_(m) = 1000 kM`
D. `Lambda_(m) = 1000 (k)/(M^(2))`

Answer

A

Explanation

Molar conductivity `(Lambda_(m))` is the conductivity per unit molar concentration and is given by the expression:
`Lambda_(m) = (kappa)/(c)`
where `c` is in mol `m^(-3)` units if `kappa` is expressed in `S m^(-)` and in mol `cm^(-3)` units it k is expressed in `S cm^(-1)`. Thus molar conductivity is usually expressed in `S m^(2) cm^(-1)` or `S cm^(2) mol^(-1)`.
`Lambda_(m)(S m^(2) mol^(-1))= (k(S m^(-1)))/("molarity" (mol L^(-1)) xx 1000 L m^(-3))`
`Lambda_(m)(S m^(2) mol^(-1))= (k(S m^(-1)) xx 1000 cm^(3) L^(-1))/("molarity" (mol L^(-1)) xx 1000 L m^(-3))`
It may be remebers that,
`S m^(2) mol^(-1) = 10000 S cm^(2) mol^(-1)`