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Both chromate and dichromate ions are in...

Both chromate and dichromate ions are in dynamic equilibrium st pH

A

6

B

8

C

4

D

10

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The correct Answer is:
To determine the dynamic equilibrium between chromate (\( \text{CrO}_4^{2-} \)) and dichromate (\( \text{Cr}_2\text{O}_7^{2-} \)) ions at a specific pH, we can follow these steps: ### Step 1: Understand the Chemical Reactions The chromate and dichromate ions are interconvertible in solution depending on the pH. The relevant reactions are: 1. **Dichromate to Chromate**: \[ \text{Cr}_2\text{O}_7^{2-} + 2 \text{OH}^- \rightleftharpoons 2 \text{CrO}_4^{2-} + \text{H}_2\text{O} \] 2. **Chromate to Dichromate**: \[ 2 \text{CrO}_4^{2-} + 2 \text{H}^+ \rightleftharpoons \text{Cr}_2\text{O}_7^{2-} + \text{H}_2\text{O} \] ### Step 2: Analyze the Effect of pH - In a **basic medium** (high pH), the equilibrium shifts towards the formation of chromate ions (\( \text{CrO}_4^{2-} \)). - In an **acidic medium** (low pH), the equilibrium shifts towards the formation of dichromate ions (\( \text{Cr}_2\text{O}_7^{2-} \)). ### Step 3: Identify the pH at Equilibrium The dynamic equilibrium between these two forms occurs at a specific pH. The transition point is typically around pH 4. At this pH, both species can coexist in solution, and the reactions can proceed in both directions: - Above pH 4, the chromate ion predominates. - Below pH 4, the dichromate ion predominates. ### Step 4: Conclusion Thus, the dynamic equilibrium between chromate and dichromate ions is established around pH 4. ### Final Answer The correct answer is that both chromate and dichromate ions are in dynamic equilibrium at **pH 4**. ---

To determine the dynamic equilibrium between chromate (\( \text{CrO}_4^{2-} \)) and dichromate (\( \text{Cr}_2\text{O}_7^{2-} \)) ions at a specific pH, we can follow these steps: ### Step 1: Understand the Chemical Reactions The chromate and dichromate ions are interconvertible in solution depending on the pH. The relevant reactions are: 1. **Dichromate to Chromate**: \[ \text{Cr}_2\text{O}_7^{2-} + 2 \text{OH}^- \rightleftharpoons 2 \text{CrO}_4^{2-} + \text{H}_2\text{O} ...
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