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Two glass plates are separated by water....

Two glass plates are separated by water. If surface tension of water is `75 dyn//cm` and the area of each plate wetted by water is `8 cm^(2)` and the distance between the plates is `0.12 mm`, then the force applied to separate the two plates is

A

`10^(2)`dyne

B

`10^(4)` dyne

C

`10^(5)` dyne

D

`10^(6)` dyne

Text Solution

Verified by Experts

The correct Answer is:
C
`F=(2Asigma)/(t)=(2xx8xx75xx10)/(0.12)dyn=10^(5)dyn`
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