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If the atmospheric pressure is 76 cm of ...

If the atmospheric pressure is 76 cm of Hg at what depth of water the pressure will becomes 2 atmospheres nearly.

A

862 cm

B

932 cm

C

982 cm

D

1033 cm

Text Solution

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The correct Answer is:
To solve the problem of finding the depth of water at which the pressure becomes 2 atmospheres, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Data:** - Atmospheric pressure (P₀) = 76 cm of Hg - We need to find the depth of water (h) where the pressure becomes 2 atmospheres. 2. **Convert Atmospheric Pressure to a Common Unit:** - Since 1 atmosphere is equivalent to 76 cm of Hg, 2 atmospheres will be: \[ P = 2 \times P₀ = 2 \times 76 \text{ cm Hg} = 152 \text{ cm Hg} \] 3. **Calculate the Pressure Difference:** - The pressure due to the water column at depth h must equal the difference between the total pressure (2 atmospheres) and the atmospheric pressure: \[ P_{\text{water}} = P - P₀ = 152 \text{ cm Hg} - 76 \text{ cm Hg} = 76 \text{ cm Hg} \] 4. **Use the Hydrostatic Pressure Formula:** - The pressure due to a column of liquid is given by: \[ P = h \cdot \rho \cdot g \] - Here, we can equate the pressure due to the water column to the pressure difference we calculated: \[ h \cdot \rho_{\text{water}} \cdot g = 76 \text{ cm Hg} \] 5. **Convert the Pressure of Mercury to Water:** - The density of mercury (ρₕ) is approximately 13.6 g/cm³, and the density of water (ρₜ) is approximately 1 g/cm³. Therefore, we can relate the heights of the mercury and water columns: \[ h_{\text{water}} \cdot \rho_{\text{water}} \cdot g = h_{\text{Hg}} \cdot \rho_{\text{Hg}} \cdot g \] - This simplifies to: \[ h_{\text{water}} = h_{\text{Hg}} \cdot \frac{\rho_{\text{Hg}}}{\rho_{\text{water}}} \] - Substituting the values: \[ h_{\text{water}} = 76 \text{ cm} \cdot \frac{13.6}{1} = 76 \cdot 13.6 = 1033.6 \text{ cm} \] 6. **Conclusion:** - The depth of water at which the pressure becomes nearly 2 atmospheres is approximately **1033.6 cm**. ### Final Answer: The depth of water required for the pressure to become 2 atmospheres is **1033.6 cm**. ---

To solve the problem of finding the depth of water at which the pressure becomes 2 atmospheres, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Given Data:** - Atmospheric pressure (P₀) = 76 cm of Hg - We need to find the depth of water (h) where the pressure becomes 2 atmospheres. ...
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Knowledge Check

  • Atmospheric pressure is measured with a ?

    A
    Hygrometer
    B
    Barometer
    C
    Hydrometer
    D
    Altimeter
  • At seal level, atmospheric pressure is:

    A
    760 cm of Hg
    B
    76 cm of Hg
    C
    0.76 cm of Hg
    D
    7.6 cm of Hg
  • The atmospheric pressure on a certain day is 732 mm Hg . What is the pressure in kPa ?

    A
    `60 kPa`
    B
    `80.6 kPa`
    C
    `77.8 kPa`
    D
    `97.6 kPa`
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