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The pressure at the bottom of a lake due...

The pressure at the bottom of a lake due to water is `4.9xx 10^(6)N//m^(2)`. What is the depth of the lake?

Text Solution

Verified by Experts

`"Pressure P"=hrhog=4.9xx10^(6)N//m^(2)`
`rho" density of water "=1000kg//m^(3),g=9.8m//s^(2)`
hence `h=(P)/(rhog)=(4.9xx10^(6))/(1000xx9.8)=500m`
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Knowledge Check

  • If pressure at half the depth of a lake is equal to 2//3 pressure at the bottom of the lake then what is the depth of the lake ?

    A
    10 m
    B
    20 m
    C
    60 m
    D
    30 m

  • A bubble of the gas released at the bottom of a lake increases to eight times the original volume when it reaches at the surface. Assuming that the atmospheric pressure is equivalent to pressure exerted by a column of water 10 m high, what is the depth of the lake

    A
    80 m
    B
    90 m
    C
    10 m
    D
    70 m

  • If the pressure at half of the lake is equal to 1/3 pressure at the bottom of the lake, what is the depth of the take? ("assume" g=10m//s^(2), atm=1xx10^(5) and rho=10^(3)kgm^(-3))

    A
    9.6m
    B
    7.5m
    C
    40m
    D
    3.2m
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