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The pressure at the bottom of a lake due...

The pressure at the bottom of a lake due to water is `4.9xx 10^(6)N//m^(2)`. What is the depth of the lake?

Text Solution

Verified by Experts

`"Pressure P"=hrhog=4.9xx10^(6)N//m^(2)`
`rho" density of water "=1000kg//m^(3),g=9.8m//s^(2)`
hence `h=(P)/(rhog)=(4.9xx10^(6))/(1000xx9.8)=500m`
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