Water raises to a height of `10 cm` in a capillary tube and mercury falls to a depth of 3.5 cm in the same capillary tube. If the density of mercury is `13.6(gm)/(c.c)` and its angle of contact is `135^(@)` and density of water is `1(gm)/(c.c)` and its angle of contact is `0^(@C)` then the ratio of surface tensions of two liquids is `(cos135^(@)=0.7)`

Options

A. `1:14`
B. `5:34`
C. `1:5`
D. `5:27`

Answer

2

Explanation

`T=(rhdg)/(2)`