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When a surface 1cm thick is illuminated ...

When a surface `1cm` thick is illuminated with light of wave length `lambda` the stopping potential is `V_(0)`, but when the same surface is illuminated by light of wavelength `3 lambda`, the stopping potential is `V_(0)/6`. The threshold wavelength for matellic surface is:

A

`4lambda`

B

`5lambda`

C

`3lambda`

D

`2lambda`

Text Solution

Verified by Experts

The correct Answer is:
B
`eV_(0)=hc(1/lambda-1/lambda_(0))(eV_(0))/6=hc(1/(3lambda)-1/lambda_(0))`
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