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When a surface 1cm thick is illuminated ...

When a surface `1cm` thick is illuminated with light of wave length `lambda` the stopping potential is `V_(0)`, but when the same surface is illuminated by light of wavelength `3 lambda`, the stopping potential is `V_(0)/6`. The threshold wavelength for matellic surface is:

A

`4lambda`

B

`5lambda`

C

`3lambda`

D

`2lambda`

Text Solution

Verified by Experts

The correct Answer is:
B
`eV_(0)=hc(1/lambda-1/lambda_(0))(eV_(0))/6=hc(1/(3lambda)-1/lambda_(0))`
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Knowledge Check

  • When a surface 1 cm thick is illuminated with light of wavelength lambda , the stopping potential is V_(0) , but when the same surface is illuminated by light of wavelength 3lambda , the stopping potential is (V_(0))/(6) . Find the threshold wavelength for metallic surface.

    A
    `4lambda`
    B
    `5lambda`
    C
    `3lambda`
    D
    `2lambda`

  • When a centimetre thick surfaces is illuminated with light of wavelength lambda , the stopping potential is V . When the same surface is illuminated by light of wavelength 2lambda , the stopping potential is V//3 . The threshold wavelength for the surface is:

    A
    `(4lambda)/(3)`
    B
    `4 lambda`
    C
    `6 lambda`
    D
    `(8lambda)/(3)`

  • When a centimeter thick surface is illuminated with light of wavelength lamda , the stopping potential is V. When the same surface is illuminated by light of wavelength 2lamda , the stopping potential is (V)/(3) . Threshold wavelength for the metallic surface is

    A
    `(4lamda)/(3)`
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