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A particle is droped from a height H. Th...

A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional to

A

`H`

B

`H^(1//2)`

C

`H^(0)`

D

`H^(-1//2)`

Text Solution

Verified by Experts

The correct Answer is:
D
Velocity of a body falling from a height `H` is given by `v=sqrt(2gH)`
We know that de-broglie wavelength `lambda=h/(mv)=h/(msqrt(2gH)) rArr =h/(msqrt(2g)sqrtH)`
Here,`h/(msqrt2g)` is a constant `phi` say `K`
So, `lambda=K1/sqrtH rArr prop 1/sqrtH rArrlambda prop H^(-1//2)`
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Knowledge Check

  • A particle is droped from a height H. The de-broglie wavelength of the particle as a funciton of height is proportional to

    A
    `H`
    B
    `H^(1//2)`
    C
    `H^(0)`
    D
    `H^(-1//2)`

  • A particle is dropped from a height H. the de-Broglie wavelength of the particle depends on height as

    A
    `H^(-1//2)`
    B
    `H^(0)`
    C
    `H^(1//2)`
    D
    `H`

  • The de Broglie wavelength lambda of a particle

    A
    is proportional to mass
    B
    is proportional to impluse
    C
    is inversely proportional to impulse
    D
    does not depend on impulse

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