A particle is droped from a height H. The de-broglie wavelength of the particle as a function of height is proportional to

Options

A. `H`
B. `H^(1//2)`
C. `H^(0)`
D. `H^(-1//2)`

Answer

D

Explanation

Velocity of a body falling from a height `H` is given by `v=sqrt(2gH)`
We know that de-broglie wavelength `lambda=h/(mv)=h/(msqrt(2gH)) rArr =h/(msqrt(2g)sqrtH)`
Here,`h/(msqrt2g)` is a constant `phi` say `K`
So, `lambda=K1/sqrtH rArr prop 1/sqrtH rArrlambda prop H^(-1//2)`