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The charge flowing through the cell on c...

The charge flowing through the cell on cloing the key `k` is equal to :

A

`(CV)/(4)`

B

CV

C

`(4)/(3)CV`

D

`(3)/(4) CV`

Text Solution

Verified by Experts

The correct Answer is:
A
`C_("net") =(3)/(4) C` when key was open `q = (3)/(4) CV`
when key was closed `3C` becomes short circuited.
Net charge on `C` is now `q = CV`
`Delta q = q - q = (CV)/(4)`.
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