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For SHM to take place force acting on th...

For `SHM` to take place force acting on the body should be proportional to `-x` or `F =- kx`. If `A` be the amplitude then energy of oscillation is `1//2KA^(2)`.
Force acting on a block is `F = (-4x +8)`. Here `F` is in newton and `x` in the position of block on x-axis in meters

A

Motion of the block is periodic but not simple harmonic

B

Motion of the block is not period

C

Motion of the block is simple harmonic about the origin, `x =0`

D

Motion of the block is simple harmonic about `x =2m`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the given force equation and determine the characteristics of the motion of the block. ### Step 1: Identify the given force equation The force acting on the block is given by: \[ F = -4x + 8 \] ### Step 2: Rearrange the force equation We can rewrite the force equation as: \[ F = -4(x - 2) \] This shows that the force can be expressed in the form of a restoring force, where the equilibrium position (mean position) is at \( x = 2 \). ### Step 3: Identify the spring constant (k) From the rearranged equation, we can see that the coefficient of \( x \) is \(-4\). Therefore, we can identify: \[ k = 4 \] ### Step 4: Determine the mean position (x₀) From the equation \( F = -k(x - x₀) \), we can see that the mean position \( x₀ \) is: \[ x₀ = 2 \] ### Step 5: Determine the amplitude (A) In simple harmonic motion (SHM), the amplitude is the maximum displacement from the mean position. Since the force equation indicates a linear restoring force, the motion can be periodic. The amplitude can be considered as the distance from the mean position to the maximum displacement. If we assume the maximum displacement is \( A \), then: \[ A = 4 \] (as inferred from the force equation) ### Step 6: Determine the type of motion Since the force is not purely proportional to \(-x\) (due to the constant term +8), the motion is not simple harmonic motion. The motion is periodic but not simple harmonic because the restoring force does not follow the form \( F = -kx \) around the origin. ### Conclusion The motion of the block is periodic but not simple harmonic due to the presence of the constant force term. ### Final Answer The motion of the block is periodic but not simple harmonic. ---

To solve the problem, we need to analyze the given force equation and determine the characteristics of the motion of the block. ### Step 1: Identify the given force equation The force acting on the block is given by: \[ F = -4x + 8 \] ### Step 2: Rearrange the force equation We can rewrite the force equation as: ...
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Knowledge Check

  • Passage IX) For SHM to take place force acting on the body should be proportional to -x or F = -kx. If A be the amplitude then energy of oscillation is 1/2 k A^(2) Force acting on a block is F=(-4x +8) . Here F is in Newton and x the position of block on x-axis in meter

    A
    motion of the block is periodic but not simple harmonic
    B
    Motion of the block is not periodic
    C
    motion of the block is simple harmonic about origin, x=0
    D
    motion of the block is simple harmonic about x=2m.
  • For SHM to take place force acting on the body should be proportional to -x or F =- kx . If A be the amplitude then energy of oscillation is 1//2KA^(2) . The amplitude of oscillation is

    A
    `4cm`
    B
    `2cm`
    C
    `1cm`s
    D
    `3cm`
  • For SHM to take place force acting on the body should be proportional to -x or F =- kx . If A be the amplitude then enegry of oscillation is 1//2KA^(2) . If enegry of oscillation is 18J , between what points does the block will oscillate?

    A
    between `x =0` nad `x =4m`
    B
    between `x =-1m` and `x =5 m`
    C
    between `x =-2` and `x =6m`
    D
    between `x =1m` and `x =3m`
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