In forced oscillation of a particle the amplitude is maximum for a frequency `omega_(2)` of the force while the energy is maximum for a frequecyomega_(2) of the force, then .

Options

A. `omega_(1) lt omega_(2)`
B. `omega_(1) gt omega_(2)`
C. `omega_(1) lt omega_(2)` when damping is small and `omega_(1) gt omega_(2)` when damping is large
D. `omega_(1) = omega_(2)`

Answer

A

Explanation

`x_(0) = (F//m)/(sqrt((omega_(0)^(2)-omega^(2))^(2)+((b omega)/(m))^(2)))` amplitude is maximum when `omega_(1) = sqrt(omega_(0)^(2)-2 gamma^(2))` and energy is maximum when `omega_(2) = omega_(0)`