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A particle in SHM has a period of 4s .It...

A particle in SHM has a period of 4s .It takes time `t_(1)` to start from mean position and reach half the amplitude. In another case it takes a time `t_(2)` to start from extreme position and reach half the amplitude. Find the ratio `t_(1)//t_(2)`

A

`(t_(1))/(t_(2))`

B

`(t_(1))/(t_(2))`

C

`(t_(1))/(t_(2)) =2`

D

`(t_(1))/(t_(2)) = 3`

Text Solution

Verified by Experts

The correct Answer is:
B
`(A)/(2) = A sin (omegat_(1)), (A)/(2) = A cos (omegat_(2))`
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Knowledge Check

  • A particle executing SHM of amplitude 4 cm and T=4 s .The time taken by it to move from position to half the amplitude is

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