Home
Class 11
PHYSICS
A long rod ABC of mass "m" and length "L...

A long rod `ABC` of mass "m" and length "L" has two particles of masses "m" and "2m" attached to it as shown in the figure. The system is initially in the horizontal position. The work to be done to keep it vertical with `A` hinged at the bottom is
.

A

`2mgL`

B

`3mgL//2`

C

`5mgL//2`

D

`3mgL`

Text Solution

Verified by Experts

The correct Answer is:
D
`W = mg L/(2) + mg "(L)/(2) + 2mgL`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • WORK POWER AND ENERGY

    NARAYNA|Exercise NCERT (Based Questions)|45 Videos

  • WORK POWER AND ENERGY

    NARAYNA|Exercise Level-V (Single Answer)|24 Videos

  • WORK POWER AND ENERGY

    NARAYNA|Exercise Level- II (C.W)|68 Videos

  • WORK , ENERGY & POWER

    NARAYNA|Exercise EXERCISE IV|43 Videos

Similar Questions

Explore conceptually related problems

Two masses m and M are attached to the strings as shown in the figure. If the system is in equilibruim, then

A uniform rod of mass M and length L with two particles m and m_(2) attached to its ends, is pivoted at its centre. The system rotates in a vertical plane with angular velocity omega .

Knowledge Check

  • Two masses m and M are attached to the strings as shown in the figure. If the system is in equilibrium, then

    A
    `tantheta=1+(2M)/(m)`
    B
    `tantheta=1+(2m)/(M)`
    C
    `cottheta=1+(2M)/(m)`
    D
    `cottheta=1+(2m)/(M)`

  • A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T_1/T_2 is:

    A
    `1:1`
    B
    `1:2`
    C
    `2:1`
    D
    `4:3`

  • A rod of mass m and length l is hinged at 'its' end and released from rest in position shown. Find the force exerted by the hinge when the rod becomes horizontal

    A
    `(mg)/4`
    B
    `(3mg)/2 cos theta`
    C
    `(mg)/4sqrt(9cos^(2)theta+1/4)`
    D
    `(mg)/2 sqrt(9 cos^(2)theta+1/4)`

    • Similar Questions

    Explore conceptually related problems

    A uniform rod of length 4 m and mass 20 kg is lying horizontal on the ground. The work done in keeping it vertical with one of its ends touching the ground, will be -

    A uniform rod of mass m and length L is suspended with two massless strings as shown in figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T_(1)//T_(2) is

    A rod PQ of mass M and length L is hinged at end P . The rod is kept horizontal by a massless string tied to point Q as shown in the figure. When string is cut, the initial angular accleration of the rod is.

    A light rod of length l has two masses m_1 and m_2 attached to its two ends. The moment of inertia of the system about an axis perpendicular to the rod and passing through the centre of mass is.

    A rod of mass M and length L is made to stand vertically. Potential energy of the rod in this position is

    Home
    Profile