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Block A has a weight of 300 N and block ...

Block `A` has a weight of `300 N` and block `B` has weight `50 N`. Calculate the distance `A` must descent form rest before it obtains a speed of `4 m//s` (Neglect the mass of cord and pulleys). `(Take g =1 0 m//s^(2))`.
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The correct Answer is:
`2`
`S_(A) = h` and `S_(B) = 2h , V_(A) = 4m//s , V_(B) = 8 m//s` From energy conservation decreases in `P.E` of `A` = Increase in `P.E.B+` Increase in `K.E` of both `A` and `B`
`300h = 50 xx 2h +(1)/(2) xx30 xx 4^(2)+(1)/(2) xx 5xx 8^(2)`
`300 h=100h + 240 + 160`,
`200 h = 400 , h = 2m`.
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