The ceiling of a long hall is `20 m` high. What is the maximum horizontal distance that a ball thrown with a speed of `40 m` can go without hitting the ceiling of hall `(g=10 ms^(-2))` ?

Explanation

To solve the problem of finding the maximum horizontal distance a ball can travel when thrown with a speed of 40 m/s without hitting the ceiling of a hall that is 20 m high, we can follow these steps:

### Step 1: Understand the motion of the ball
The ball is projected at an angle θ with an initial speed of 40 m/s. The motion can be divided into horizontal and vertical components.

### Step 2: Calculate the vertical motion
The vertical motion of the ball can be described by the equation of motion under gravity. The maximum height (h) reached by the ball can be calculated using the formula:
\[ h = \frac{(v_{y})^2}{2g} \]
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