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Find the point in which the line (x+1)/-...

Find the point in which the line `(x+1)/-1=(y-12)/5=(z-7)/2` cuts the surface `11x^2 - 5y^2+z^2 = 0`.

A

`(2,-3,1)`

B

`(2,3,-1)`

C

`(1,-2,3)`

D

`(1,2,-3)`

Text Solution

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The correct Answer is:
A
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The points in which the line (x+1)/-1=(y-12)/5=(z+7)/2 cuts the surface 11x^(2)-5y^(2)+z^(2)=0 are ….......

The distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/2=(y+1)/4=(z-2)/12 and the plane x-y+z=5 is

Knowledge Check

  • The line (x-3)/1=(y-4)/2=(z-5)/2 cuts the plane x+y+z=17 at

    A
    (3,4,5)
    B
    (4,6,7)
    C
    (4,5,8)
    D
    (8,4,5)

  • Statement 1: A point on the line (x+2)/3=(y+1)/2=(z-3)/2 at a distance 3sqrt(2) from the point (1,2,3) lies on the lne (x+7)/5=(y+t)/4=(z-2)/1 Statement 2: If d is the distance between the point (-1,-5,-10) and the point of intersectionof the line (x-2)/3=(y+1)/4=(z-2)/12 with the plane x-y+z=5 then d=13

    A
    Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1.
    B
    Statement-1 is True, Statement-2 is True, Statement-2 is not a correct explanation for Statement-1.
    C
    Statement-1 is True, Statement-2 is False.
    D
    Statement-1 is False, Statement-2 is True.

  • The distance of the point (-1, -5, -10) from the point of intersection of the line (x-2)/(2)=(y+1)/(4)=(z-2)/(12) and the plane x-y+z=5 is

    A
    `2sqrt(11)`
    B
    `sqrt(126)`
    C
    `13`
    D
    `14`

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    Find the coordinates of the point where the line (x-2)/(3)=(y+1)/(4)=(z-2)/(2) intersect the plane x-y+z-5=0. Also,find the angel between the line and the plane.

    Find the coordinates of the point,where the line (x-2)/(3)=(y+1)/(4)=(z-2)/(2) intersects the plane x-y+z-5=0 .Also find the angle between the line and the plane.

    (i) Find the angle between the line : (x + 1)/(2) = (y)/(3) = (z - 3)/(6) and the plane 10x + 12y - 11z = 3 (ii) Find the angle between the line : (x + 1)/(2) = (y -1)/(2) = (z -2)/(4) and the plane 2x + y - 3z + 4 =0 . (iii) Find the angle between the plane 2x + 4y - z = 8 and line (x - 1)/(2) = (2 - y)/(7) = (3z + 6)/(12) (iv) Find the angle between the line (x - 1)/(3) = (3 -y)/(-1) = (3z + 1)/(6) and the plane 3x - 5y + 2z = 10 .

    Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) and plane x-y+z=5 .

    The point of intersection of the lines (x-1)/2=(y-2)/3=(z-3)/4 and (x-4)/5=(y-1)/2=z is

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