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[Co(CN)(6)]^(3-) and [CoF(6)]^(3-) both ...

`[Co(CN)_(6)]^(3-)` and `[CoF_(6)]^(3-)` both are octahedral complexes. Then what is the difference between the two ?

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To differentiate between the two octahedral complexes `[Co(CN)_(6)]^(3-)` and `[CoF_(6)]^(3-)`, we can analyze their electronic configurations, hybridization, magnetic properties, and the nature of the ligands involved. ### Step-by-Step Solution: 1. **Identify the Oxidation State of Cobalt**: - In both complexes, cobalt is in the +3 oxidation state. - For `[Co(CN)_(6)]^(3-)`, the cyanide (CN) ligand has a charge of -1. Thus, with 6 CN ligands, the total charge contributed by ligands is -6. Therefore, the overall charge of the complex is -3, confirming Co is +3. - Similarly, for `[CoF_(6)]^(3-)`, the fluoride (F) ligand also has a charge of -1. With 6 F ligands, the total charge is again -6, confirming Co is +3. ...
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[CoF_(6)]^(3-) is

[Co(NH_(3))_(6)]^(3+) & [CoF_(6)]^(3-) both are complexes of Co(III), but [Co(NH_(3))_(6)]^(3+) is diamagnetic while [Co(F_(6)]^(3-) is paramagnetic with mu=4.90 BM . Explain.

Knowledge Check

  • For [FeF_(6)]^(3-) and [CoF_(6)]^(3-) , the correct statement is

    A
    both are coloured
    B
    both are colourless
    C
    `[FeF_(6)]^(3-)` is coloured and `[CoF_(6)]^(3-)` is colourless
    D
    `[FeF_(6)]6(3-)` is colourless and `[CoF_(6)]^(3-)` is coloured

  • For [FeF_(6)]^(3-) and [CoF_(6)]^(3-) , the statement that is correct is :

    A
    both are coloured
    B
    both are colourless
    C
    `[FeF_(6)]^(3-)` is colored and `[CoF_(6)]^(3-)` is colorless
    D
    `[FeF_(6)]^(3-)` is colorless and `[CoF_(6)]^(3-)` is colored

  • For [FeF_(6)]^(3-)" and "[CoF_(6)]^(3-) , the statement that is correct is :

    A
    both are coloured
    B
    both are colourless
    C
    `[FeF_(6)]^(3-)` is coloured and `[CoF_(6)]^(3-)` is colourless
    D
    `[FeF_(6)]^(3-)` is colourless and `[CoF_(6)]^(3-)` is coloured

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    What is CN of metal atom in an octahedral complex ?

    [CoF_(6)]^(3-) forms outer orbital complexes while (Co(CN)_(6)]^(3-) forms inner orbital complexes. Why

    The shape of [CoF_(6)]^(-3) is

    The complex ions [Fe(CN)_(6)]^(3-) and [Fe(CN)_(6)]^(4-) :

    Consider the following two complex ions : [CoF_(6)]^(3-) and [Co(C_(2)O_(4))_(3)]^(3-) . Which of the following statement(s) is/are false ? I. Both are octahedral II. [Co(C_(2)O_(4))_(3)]^(3-) is diamagnetic while [CoF_(6)]^(3-) is paramagnetic . III. Both are outer orbital complexes . IV. In both the complexes the central metal is in the same oxidation state .

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