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Comprehension # 8 A factory, producing...

Comprehension # 8
`A` factory, producing methanol, is based on the reaction:
`CO+2H_(2)hArrCH_(3)OH`
Hydrogen `&` carbon monoxide are obtained by the reaction
`CH_(4)+H_(2)OhArrCO+3H_(2)`
Three units of factory namely, the "reformer" for the `H_(2)` and `CO` production, the "methanol reactor" for production of methanol and a "separator" to separate `CH_(3)OH` from `CO` and `H_(2)` are schematically shown in figure.

four positions are indicated as `alpha,beta,gamma` and `delta`. The flow of methanol at position `gamma` is `10^(3)mol//sec`. The factory is so designed that `(2)/(3)` of the `CO` is converted to `CH_(3)OH`. Excess of `CO` and `H_(2)` at position `delta` are used to heat the first reaction. Assume that the reformer reaction goes to completion. At the position `(beta)` mole ratio of `CO` to `H_(2)` is `(1)/(3)`
`CO+2H_(2)hArrCH_(3)OH " "DeltaH_(r)=-100 R`
What is the flow of `CO` and `H_(2)` at position `(beta)` ?

A

`CO : 1500mol//sec., H_(2) : 2000 mol//sec`.

B

`CO : 1500mol//sec., H_(2) : 3000 mol//sec`.

C

`CO : 1000mol//sec., H_(2) : 2000 mol//sec`.

D

`CO : 1500mol//sec., H_(2) : 4500 mol//sec`.

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(,CH_(4)+H_(2)OrarrCO,+,3H_(2)),(," "(3)/(2)xx10^(3),,3):}`
`CO+2H_(2) rarr CH_(3)OH`
`10^(3)" "2xx10^(3)" "10^(3)("moles/sec")`
`("total" CO = (3)/(2) xx 10^(3))`
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