1 mole heptane `(V.P = 92 mm of Hg)` is mixed with 4 mol. Octane `(V.P = 31` mm of `Hg)`, form an ideal solution. Find out the vapour pressure of solution.

Explanation

To find the vapor pressure of the solution formed by mixing 1 mole of heptane with 4 moles of octane, we can use Raoult's Law. Here’s a step-by-step solution:

### Step 1: Identify the Given Data
- Vapor pressure of pure heptane (P₁⁰) = 92 mm of Hg
- Vapor pressure of pure octane (P₂⁰) = 31 mm of Hg
- Moles of heptane (n₁) = 1 mole
- Moles of octane (n₂) = 4 moles

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