Home
Class 12
CHEMISTRY
A certain substance A tetramerizes in wa...

A certain substance `A` tetramerizes in water to the extent of `80%`. A solution of `2.5 g` of `A` in `100 g` of water lowers the freezing point by `0.3^(@)C`. The molar mass of `A` is
a.`120` , b.`61` ,c.`60` ,d.`62`

A

122

B

31

C

244

D

62

Text Solution

Verified by Experts

The correct Answer is:
D

`alpha = (1-i)/(1-(1)/(n))`
`0.8 = (1-i)/(1-(1)/(n))i = 0.4`
`DeltaT = iK_(f) xx m`
`0.3 xx 0.4 xx 1.86 xx (w_(B) xx 1000)/(m_(a) xx w_(A))`
`0.3 xx 0.4 xx 1.86 xx (2.5 xx 1000)/(m_(a) xx 100)`
`m_(a) = 62`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLUTIONS

    ALLEN|Exercise EXERCISE -01|53 Videos
  • SOLUTIONS

    ALLEN|Exercise EXERCISE -02|44 Videos
  • SOLUTIONS

    ALLEN|Exercise EXERCISE -05 [B]|22 Videos
  • S-BLOCK ELEMENTS

    ALLEN|Exercise EXERCISE -3|1 Videos
  • Some Basic Concepts of Chemistry (Mole concept)

    ALLEN|Exercise All Questions|39 Videos

Similar Questions

Explore conceptually related problems

A solution made by dissolving 0.32 of a new compound in 25g of water has freezing point -0.201^(@)C .the molecular mass of the new compound.

A certain mass of substance in 10 g of benzene lowers the freezing point by 1.28^(@)C and in 100 g of water lowers the freezing point by 1.395^(@)C separately. If the substance has normal molecular weight in benzene and completely dissociated in water, calculate number of moles of ions formed by its 1 mole dissociation in water (K_(f_("water"))=1.86, K_(f_("benzene"))=5.00)

Knowledge Check

  • A solution containing 6.8 g on non-ionic solute in 100 g of water was found to freeze at -0.93^@C . The molar mass of solute is (K_b= 1.86^@C m^(-1))

    A
    13.6
    B
    34
    C
    68
    D
    136
  • 6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

    A
    60 g/mole
    B
    180 g/mole
    C
    120 g/mole
    D
    240 g/mole
  • 6 g of a substance is dissolved in 100 g of water depresses the freezing point by 0.93^(@)C . The molecular mass of the substance will be: ( K_(f) for water = 1.86^(@)C /molal)

    A
    60 g/mole
    B
    180 g/mole
    C
    120 g/mole
    D
    240 g/mole
  • Similar Questions

    Explore conceptually related problems

    0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567 ^(@)C . The molecular mass of the substance is _____ (K_(f) = 5.12 K kg mol ^(-1))

    A certain mass of a substance when dissolved in 100g C_(6)H_(6) lowers the freezing point by 1.28^(@)C . The same mass of solute dissolved in 100g of water lowers the freezing point by 1.40^(@)C . If substance has normal molecular mass in benzene and is completely dissociated in water, into how many ions does it dissociate in water, K_(f) for H_(2)O and C_(6)H_(6) are 1.86 and 5.12 K mol^(-1) kg respectively

    A certain mass of a substance when dissolved in 100 g C_(6)H_(6) lowers the freezing point by 1.28^(@) . The same mass of the solute dissolved in 100 g of water lowers the freezing point by 1.40^(@) . If the substance has normal molecular mass in benzene and is completely dissociated in water, into how many ions does it dissociate in water ? K_(f) for H_(2)O and C_(6)H_(6) are 1.86 and "5.12 K kg mol"^(-1) respectively.

    When 250 mg of eugenol is added to 100 g of camphor (K_(f) = 39.7K "molality"^(-1)) , it lowered the freezing point by 0.62^(@)C . The molar mass of eugenol is:

    When 250 mg of eugenol is added to 100 g of camphor (k_(f)=39.7" molality"^(-1)) , it lowered the freezing point by 0.62^(@)C . The molar of eugenol is :