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A charge particle q of mass is placed at...


A charge particle q of mass is placed at a distance d from another charge particle -2q of mass 2 m in a uniform magnetic field B as shown if particle are projected towareds each other with equal speed `v_(0)`, so that the two particle touches each other without collision during its motion (Assume only force due to magnetic field acts on the particle)

A

`(qBd)/(m)`

B

`(qBd)/(2m)`

C

`(2qBd)/(m)`

D

`(3qBd)/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
B
`d=(mv_(0))/(qB)+(2mv_(0))/(2qB)`
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Knowledge Check

  • The path of a charged particle in a uniform magnetic field, when the velocity and the magnetic field are perpendicular to each other is a

    A
    circle
    B
    parabola
    C
    helix
    D
    straight line

  • The force acting on a particle of charge q moving in a uniform magnets field with velocity v is

    A
    parallel to both `vecv` and `vecB`
    B
    perpendicular to both `vecv` and `vecB`
    C
    parallel to `vecv` and perpendicular to `vecB`
    D
    perpendicular to `vecv` and parallel to `vecB`

  • A charged particle of mass m and charge q describes circular motion of radius r in a uniform magnetic field of strength B. The frequency of revolution is

    A
    `(3Bq)/(2pim)`
    B
    `(3Bq)/(2pim)`
    C
    `(2pim)/(2Bq)`
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