A charge particle q of mass is placed at a distance d from another charge particle -2q of mass 2 m in a uniform magnetic field B as shown if particle are projected towareds each other with equal speed `v_(0)`, so that the two particle touches each other without collision during its motion (Assume only force due to magnetic field acts on the particle)

Options

A. `(qBd)/(m)`
B. `(qBd)/(2m)`
C. `(2qBd)/(m)`
D. `(3qBd)/(2m)`

Answer

B

Explanation

`d=(mv_(0))/(qB)+(2mv_(0))/(2qB)`