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The solution set of inequation |x^(2)-2x...

The solution set of inequation `|x^(2)-2x|+|x-4|gt|x^(2)-3x+4|` is a subset of

A

`(0, oo)`

B

`(0, 4)`

C

`(0, 2)`

D

`(4, oo)`

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The correct Answer is:
To solve the inequality \( |x^2 - 2x| + |x - 4| > |x^2 - 3x + 4| \), we will follow these steps: ### Step 1: Analyze the expressions inside the absolute values We need to identify the points where the expressions inside the absolute values change their signs. The expressions are: 1. \( x^2 - 2x = x(x - 2) \) 2. \( x - 4 \) 3. \( x^2 - 3x + 4 \) **Finding the roots:** - For \( x^2 - 2x = 0 \): - \( x(x - 2) = 0 \) gives \( x = 0 \) and \( x = 2 \). - For \( x - 4 = 0 \): - \( x = 4 \). - For \( x^2 - 3x + 4 = 0 \): - The discriminant is \( (-3)^2 - 4 \cdot 1 \cdot 4 = 9 - 16 = -7 \) (no real roots). Thus, the critical points are \( x = 0, 2, 4 \).

To solve the inequality \( |x^2 - 2x| + |x - 4| > |x^2 - 3x + 4| \), we will follow these steps: ### Step 1: Analyze the expressions inside the absolute values We need to identify the points where the expressions inside the absolute values change their signs. The expressions are: 1. \( x^2 - 2x = x(x - 2) \) 2. \( x - 4 \) 3. \( x^2 - 3x + 4 \) ...
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