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Two containers of equal volume enclose e...

Two containers of equal volume enclose equal masses of hydrogen and helium at `300K`. Find (i) the ratio of pressure and (ii) the ratio of total `K.E.` of all the molecules of the two gases.

Text Solution

Verified by Experts

The correct Answer is:
`P_(H_(2)) = 2P_(He), (kE_(H_(2)))/(kE_(He)) = (10)/(3)`
`V_(H2) = V_(He)`
`m_(H2) = m_(He), T = 300 K`
(i) `P_(H2) V_(H2) = n_(H2) RT ………(i)`
`P_(He). V_(He) = n_(He) = RT ……..(ii)`
`(P_(H_(2)))/(P_(He)) = ((m_(H_(2))//2))/(m_(He)//4)`
`rArr P_(H2) = 2P_(He)`
(ii) `K.E. = (f)/(2)nRT`
`(KE_(H_(2)))/(KE_(He)) =(f_(H_(2).n_(H_(2))))/(f_(He).n_(He)) =(5((m_(H_(2)))/(2)))/(3((m_(He))/(4))) =(10)/(3)`
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