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The ratio of r.m.s speed to the r.m.s an...

The ratio of r.m.s speed to the r.m.s angular speed of a diatomic gas at certain temperature is (assume m =mass of one molecule, M=molecular mass, I=moment of inertia of the molecules )

A

`sqrt(3/2)`

B

`sqrt((3I)/(2M))`

C

`sqrt((3I)/(2m))`

D

1

Text Solution

Verified by Experts

The correct Answer is:
C

`1/2 mV^(2)=3/2 kT`, `1/2 I omega^(2)=2/2 kT` ,`V/(omega)=sqrt((3I)/(2m))`
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Knowledge Check

  • The ratio of average speed of an oxygen molecule to the r.m.s. speed of a N_(2) molecule at the same temperature is :

    A
    `((3pi)/(7))^(1//2)`
    B
    `((7)/(3pi))^(1//2)`
    C
    `((3)/(7pi))^(1//2)`
    D
    `((7pi)/(3))^(1/2)`
  • What will be the r.m.s. speed of a gas at 800^(@)K ?

    A
    Four times the value of 200 K
    B
    Half the value at 200 K
    C
    Twice the value at 200 K
    D
    Same as at 200 K
  • At what temperature is the r.m.s velocity of a hydrogen molecule equal to that of an oxygen molecule at 24^@C ?

    A
    `80K`
    B
    `-73K`
    C
    `3K`
    D
    `20K`
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