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One end of a steel rod (K =42 J//m-s-^(@...

One end of a steel rod (`K =42 J//m-s-^(@)C)` of length `1.0m` is lept in ice at `0^(@)C` and the other end is kept in boiling water at `100^(@)C`. The area of cross-section of the rod is `0.04 cm^(2)`. Assuming no heat loss to the atmosphere, find the mass of the ice melting per second. Latent heat of fusion of ice `= 3.36 xx 10^(5) J//kg`.

Text Solution

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The correct Answer is:
`5 xx 10^(-5) g//s`
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Knowledge Check

  • One end of conducting rod is maintained at temperature 50^(@)C and at the other end ice is melting at 0^(@)C . The rate of melting of ice is doubled if:

    A
    the temperature is made `200^(@)C` and the area of cross-section of the rod is doubled
    B
    the temperature is made `100^(@)C` and the length of the rod is made four time
    C
    area of cross-section of the rod is halved and length is doubled.
    D
    the temperature is made `100^(@)C` and area of cross-section of rod and length both are doubled.
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