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A particle moves along a path ABCD as sh...

A particle moves along a path `ABCD` as shown in the figure. Then the magnitude of net displacement of the particle from position `A` to `D` is:

A

`10 m`

B

`5sqrt(2) m`

C

`9m`

D

`7sqrt(2) m`

Text Solution

Verified by Experts

The correct Answer is:
D
As seen from the figure

the displacement is `sqrt((AF)^(2)+(FD)^(2)) =7sqrt(2) m`
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Knowledge Check

  • The velocity - time graph of a particle moving along a straight line is shown in the figure given below The displacement of the particle in 5 second is

    A
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