Two objects are moving along the same st...

Two objects are moving along the same straight line. They cross a point A With an acceleration a, 2a and velocity 2u, u at time `t = 0.` The distance moved by the object when one overtakes the

`(6u^(2))/(a)`

`(2u^(2))/(a)`

`(4u^(2))/(a)`

None of these

Text Solution

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The correct Answer is:

Let both will meet at point `B`
`x=2ut+1/2at^(2)`
`x=ut+(1)/(2)(2a)t^(2)`
So `2ut+(1)/(2)at^(2)=ut+at^(2)`
`ut=(1)/(2)at^(2)rArrt=(2u)/(a)`
So `x=2u((2u)/(a))+(1)/(2)a((2u)/(a))^(2)=(6u^(2))/(a)`

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Two objects moving along the same straight line are leaving point A with an acceleration a , 2 a and velocity 2 u, u respectively at time t = 0 . The distance moved by the object with respect to point A when one object overtakes the other is :

`(3 u^2)/(a)`

`(2 u^2)/(a)`

`(4 u^2)/(a)`

`(6 u^2)/(a)`

Average velocity of a particle moving in a straight line, with constant acceleration a and initial velocity u in first t seconds is.

`u + (1)/(2) at`

`u + at`

`(u + at)/(2)`

`(u)/(2)`

At the start of a motion along a line the initial velocity is u and acceleration is at. The final velocity vafter time t, is

`v= u + at`

`v = u + at^(2)`

`v = u +(1)/(2) at^(2)`

`v = at^(2)`