Home
Class 11
PHYSICS
Two bikes A and B start from a point. A ...

Two bikes `A and B` start from a point. A moves with uniform speed `40 m//s and B` starts from rest with uniform acceleration `2 m//s^2`. If `B` starts at `t = 10` and `A` starts from the same point at `t = 10 s`, then the time during the journey in which `A` was ahead of `B` is :

A

`20s`

B

`8s`

C

`10s`

D

`A` is never ahead of `B`

Text Solution

Verified by Experts

The correct Answer is:
D
`A` will be ahead of `B` when `X_(A)gtX_(B)`
`40(t-10)gt(0)t+(1)/(2)(2)t^(2)`
as `A` is `10sec. `late than `B`.
`rArr t^(2)-40t+4 lt0`
`rArr (t-20)^(2) lt0`
Which is not possible . So `A` will never to ahead at `B`.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 39|3 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 40|5 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise Dpp 37|8 Videos

  • CURRENT ELECTRICITY

    RESONANCE|Exercise Exercise|54 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE|Exercise Advanced Level Problems|9 Videos

Similar Questions

Explore conceptually related problems

A train starting from rest moves with a uniform acceleration of 0.2 m//s^(2) for 5 minutes . Calculate the speed acquired and the distance travelled in this time.

A body starts from rest with a uniform acceleration of 8 m//"sec"^(2) . Then the time it will take in traversing the second metre of its journey is

Knowledge Check

  • A body starts from rest and then moves with uniform acceleration. Then.

    A
    Its displacement is directly proportional to square of time
    B
    Its displacement is inversely proportion to the square of the time.
    C
    It may move along a circle.
    D
    It always moves in a straight line.

  • A body starting from rest and moving with uniform acceleration will have

    A
    `v prop t`
    B
    `v prop s`
    C
    `v prop t`
    D
    `v prop sqrt(t)`

  • A body starting from rest and has uniform acceleration 8 m//s^(2) . The distance travelled by it in 5^(th) second will be

    A
    36 m
    B
    40 m
    C
    100 m
    D
    200 m

    • Similar Questions

    Explore conceptually related problems

    two cars start moving from rest with uniform acceleration a=4 m//s^(2) and 8 m//s^(2) towards each other from points A and B. the distance between points is 96 m

    Two bodies A and B start from rest from the same point with a uniform acceleration od 2 ms^(-2) . If B starts one second later, then the two bodies are separated , at the end of the next second, by

    Two cars A and B are at rest at same point initially. If A starts with uniform velocity of 40 m/sec and B starts in the same direction with constant acceleration of 4m//s^(2) , then B will catch A after :

    Two cars A and B are at rest at the origin O. If A starts with a uniform velocity of 20 m// s and B starts in the same direction with a constant acceleration of 2 m//s^(2) , then the cars will meet after time

    A car starts from rest and moves with a uniform acceleration for 2 s. After that it starts to move with a uniform deceleration of 4 m//s^2 . The acceleration of the body if it takes 3 s for the car to stop is

    Home
    Profile