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A glass ball collides with a smooth hori...

A glass ball collides with a smooth horizontal surface (`xz` plane) with a velocity `V = ai- bj`. If the coefficient of restitution of collision be `e`, the velocity of the ball just after the collision will be

A

`hat(i)+b hat(j)`

B

`ahat(i)+e b hat(j)`

C

`a hat(i)-b hat(j)`

D

`ahat(i)-e b hat(j)`

Text Solution

Verified by Experts

The correct Answer is:
B
A collision which is not elastic changes only the normal component of velocity .
Here the normal component is `-b`. Hence it become `(+eb)`
after collision keeping the `x-` component (tangential)
as begore collision.
`rArr vec(v)_(f)=ahat(i)+ebhat(j)`

Hence `(B)`.
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Knowledge Check

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