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A stone of mass M is tied at the end of ...

A stone of mass M is tied at the end of a string, is moving in a circle of radius R, with a constant angular velocity `omega`. The total work done on the stone, in any half circle, is:

A

`pi MR^(2)omega^(2)`

B

`2 MR^(2) omega^(2)`

C

`MR^(2)omega^(2)`

D

0

Text Solution

Verified by Experts

The correct Answer is:
D
`(` Easy `)` Since there is no change in kinetic energy of stone, the total work doen on stone in any duration is zero.
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Knowledge Check

  • A stone of mass m is tied to a strin and is moved in a vertical circle of radius r making n revolution per minute. The total tension in the string when the stone is its lowest point is.

    A
    `mg`
    B
    `m(g+pinr^(2)`
    C
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    D
    `m(g+(pi^(2)n^(2)r)/(900))`

  • A small steel shphere tied at the end of a string is whirled in a horizontal circle with uniform angular velocity omega the string is suddently pulled so that the radius of the circle is halved .If omega_(2) is the angular velocity then

    A
    `omega_(1)=omega_(2)`
    B
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    C
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    D
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    D
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