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A bar of mass M and length L is in pure ...

A bar of mass `M` and length `L` is in pure traslatory motion with its of mass velocity `V` . It collides with and sticks to a second identical bar which is initially at rest . `(` Assume that it bocomes one composite bar of length `2L)`. The angular velocity of the composite bar will be

A

`(3)/(4)(V)/(L)` clockwise

B

`(4)/(3)(VL)/(L)` clockwise

C

`(3)/(4)(V)/(L)` counterclockwise

D

`(V)/(L)` counterclockwise

Text Solution

Verified by Experts

The correct Answer is:
C
Cons. Of ang. Momentum about `P` gives
`MV(L)/(2)=((2M)(2L)^(2))/(12)omega`
`(V)/(2)=(2Lomega)/(3)`
`omega=(3V)/(4L), ` counterclockwise `Ans . (C )`
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