Figure shows a uniformly charges hemispherical shell. The direction of electric field at point `p` that is off centre (but in the plane of the largest circle of the hemisphere), will be along

Options

A. `pa`
B. `pb`
C. `pc`
D. `pd`

Answer

B

Explanation

Let electric field at pt 'p' has both 'x' and y component
So similar electric field will be for other hemisphere (upper half)
Now lets overlap both

`(E_("net"))_(p) = 2E_(x)` and it should be zero (as E inside a full shell = 0)
So `E_(x) = 0`, so electric field at 'p' is purely in y direction
.