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One mole of an ideal monoatomic gas is m...

One mole of an ideal monoatomic gas is mixed with one mole of an equimolar mixture of monoatomic and diatomic ideal gases. Find the value of `lambda= (C_P /C_v)` for the final mixture

A

`8/7`

B

`19/12`

C

`11/7`

D

`8/5`

Text Solution

Verified by Experts

The correct Answer is:
C
`gamma=(15/2R+1(1/25/2R+1/2 7/2R))/(1 3/2R+1(1/2 3/2+R+1/2 5/2R)) =11/7`
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Knowledge Check

  • One mole of an ideal monoatomic gas is mixed with 1 mole of an ideal diatomic gas. The molar specific heat of the mixture at constant volume is

    A
    4 cal
    B
    6 cal
    C
    8 cal
    D
    3 cal

  • 10 mol of an ideal monoatomic gas at 10 ^(@)C is mixed with 20 mol of another monoatomic gas at 20^(@) C then temperature of the mixture is

    A
    ` 15.5^(@)C `
    B
    ` 15 ^(@) C`
    C
    ` 16^(@)C `
    D
    ` 16.6^(@) C`

  • 10 moles of an ideal monoatomic gas at 10^(@)C are mixed with 20 moles of another monoatomic gas at 20^(@)C . Then the temp. of the mixture is

    A
    `15.5^(@)C`
    B
    `15^(@)C`
    C
    `16^(@)C`
    D
    `16.6^(@)C`
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