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An electron is placed just in the middle...

An electron is placed just in the middle between two long fixed line charges of charge density `+lambda` each. The wires are in the xy plane (do not consider gravity)

A

The equilibrium of the electron will be stable along x-direction

B

the equilibrium of the electron will be stable along y-direction

C

the equilibrium of the electron will be unstable along y-direction

D

the equilibrium of the electron will be stable along z-direction

Text Solution

Verified by Experts

The correct Answer is:
D
If we displace the electron slightly towards X direction, it will thrown away towards right.
so eq. is unstable along x direction.
if we displace the electron slightly towards y direction, no Extra force will act. So eql. Is neutral along y axis . If we displace the electron towards z direction, it will be attract and try to come to eql. positron. so eql. is stable along z direction.
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Knowledge Check

  • The electric field intensity due to a thin infinity long straight wire of uniform linear charge density lambda at O is-

    A
    `(lambda)/(2pi epsilon_(0)R)`
    B
    `(lambda sqrt(2))/(2pi epsilon_(0)R)`
    C
    `(lambda sqrt(5))/(2pi epsilon_(0)R)`
    D
    zero

  • A charge particle q is released at a distance R_(@) from the infinite long wire of linear charge density lambda . Then velocity will be proportional to (At distance R from the wire)

    A
    `R^(3)`
    B
    `e^(R//R_(0))`
    C
    `R^(2)`
    D
    `[n((R)/(R_(0)))]^(-1//2`

  • An electron moves straight inside a charged paralle plane capacitor of uniform charge density sigma . The space between the plates is filled with uniform magnetic field of intensity B, as shown in the figure. Neglecting effect of gravity, the time of straight line motion of the electron in the capacitor is

    A
    `(epsi_(0)iB)/(sigma)`
    B
    `(sigma)/(epsi_(1) iB)`
    C
    `(epsi_(2)B)/(sigma)`
    D
    `(sigma)/(epsi_(1)B)`
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