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An element of atomic number 9 emits K(al...

An element of atomic number 9 emits `K_(alpha)` X-ray of wavelength `lamda`. Find the atomic number of the element which emits `K_(alpha)` X-ray of wavelength `4lamda`.

A

`11`

B

`44`

C

`6`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
C

For `K_(alpha)rArrsqrt(v)prop(z-1) rArr(1)/(sqrt(lambda))prop(z-1)`
or `(1)/((z-1)^(2))`.....(i)
`4lambdaprop(1)/((z'-1)^(2))`.....(ii)
`rArr (1)/(4)=((z'-1)^(2))/((z-1)^(2)) rArr(z'-1)/(z-1)=(1)/(2)`
`rArr 2z'-2=z-1 rArr2z'-2=11-1=10 rArr z'=6`
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Knowledge Check

  • If the wavelength of K_(alpha) radiation emitted an atom of atomic number Z = 41 is lambda , then the atomic number for an atom that emits K_(alpha) radiation with the wavelength 4lambda , is

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  • Calculate the K_(alpha) x-ray wavelength for a gold atom (Z=79) .

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    B
    `2.00xx10^(-11)m`
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